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Strange IIF Parser Behavior

Hey @Rich Howard,


I noticed today that the parser will error out if I use IIF(X > 0, Y, Z), but accepts IIF(X <= 0, Z, Y). Any idea what's going on there?

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Rich Howard
Rich Howard
5 days ago

Eli, Sorry for the delay. I have been trying versions of the following and can't reproduce this. Do you have a simple example that errors?


This is for the User Defined equation...

X=0;
Y=1;
Z=0;
User = IIF(X>0,Y,Z)

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