To see this working, head to your live site.

Strange IIF Parser Behavior

Hey @Rich Howard,

I noticed today that the parser will error out if I use IIF(X > 0, Y, Z), but accepts IIF(X <= 0, Z, Y). Any idea what's going on there?

1 comment

Comments (1)

Jun 01, 2023

Eli, Sorry for the delay. I have been trying versions of the following and can't reproduce this. Do you have a simple example that errors?

This is for the User Defined equation...

X=0;
Y=1;
Z=0;
User = IIF(X>0,Y,Z)