Hey @Rich Howard,I noticed today that the parser will error out if I use IIF(X > 0, Y, Z), but accepts IIF(X <= 0, Z, Y). Any idea what's going on there?
Eli, Sorry for the delay. I have been trying versions of the following and can't reproduce this. Do you have a simple example that errors?
This is for the User Defined equation...
X=0; Y=1; Z=0; User = IIF(X>0,Y,Z)